2x^2-56x+104=0

Solution for 2x^2-56x+104=0 equation:

2x^2-56x+104=0

a = 2; b = -56; c = +104;
Δ = b2-4ac
Δ = -562-4·2·104
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-48}{2*2}=\frac{8}{4}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+48}{2*2}=\frac{104}{4}
=26
$